
Simple Serial Dilution Calculation
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A serial dilution is any dilution in which the concentration decreases by the same factor in each successive step. In serial dilutions, you multiply the dilution factors for each step. The dilution factor or the dilution is the initial volume divided by the final volume. #DF = V_i/V_f# For example, if you add a 1 mL sample to 9 mL of diluent to get 10 mL of solution, #DF = V_i/V_f# = #(1'mL')/(10'mL') = 1/10#. This is a 1:10 dilution. Example 1 What is the dilution factor if you add 0.2 mL of a stock solution to 3.8 mL of diluent? #V_f# = 0.2 mL + 3.8 mL = 4.0 mL #DF = V_i/V_f# = #(0.2'mL')/(4.0'mL') = 1/20#.
This is a 1:20 dilution. Example 2 If you did the above dilution four times, what would be the final dilution factor? Solution 2 Remember that serial dilutions are always made by taking a set quantity of the initial dilution and adding it successively to tubes with the same volume. So you multiply each successive dilution by the dilution factor. You would transfer 0.2 mL from Tube 1 to 3.8 mL of diluent in Tube 2 and mix.
Dilutions: Explanations and Examples of Common Methods. There are many ways of expressing concentrations and dilution. The following is a brief explanation of some ways of calculating dilutions that are common in biological science and often used at Quansys Biosciences. The solution dilution calculator tool calculates the volume of stock concentrate to add to achieve a specified volume and concentration. The calculator uses the formula M 1 V 1 = M 2 V 2 where '1' represents the concentrated conditions (i.e. Stock solution Molarity and volume) and '2' represents the diluted conditions (i.e. Desired volume.
Then transfer 0.2 mL from Tube 2 to 3.8 mL of diluent in Tube 3 and mix. Repeat the process until you have four tubes. The dilution factor after four dilutions is #DF = 1/20 × 1/20 × 1/20 × 1/20 = 1/160000# = 1:160 000 If the concentration of the original stock solution was 100 µg/µL, the concentration in Tube 4 would be 100 µg/µL × #1/160000# = 6.25 × 10⁻⁴ µg/µL Hope this helps. 